What-is-the-escape-velocity-from-the-surface-of-a-planet-with-two-third-of-the-earth-s-gravity-but-the-same-radius-

Question Number 10355 by Tawakalitu ayo mi last updated on 05/Feb/17

What is the escape velocity from the surface

of a planet with two third of the {earth}^{'} s

gravity but the same radius .

Commented by Tawakalitu ayo mi last updated on 05/Feb/17

i will reduce it sir .

Answered by mrW1 last updated on 05/Feb/17

E s c a p e v e l o c i t y v = \sqrt{\frac{2 G m}{R}}

w i t h G = u n i v e r s a l g r a v i t a t i o n a l c o n s t a n t

m = M a s s o f p l a n e t

R = R a d i u s o f p l a n e t

\frac{v_{x}}{v_{e a r t h}} = \sqrt{\frac{m_{x}}{m_{e a r t h}}} = \sqrt{\frac{2}{3}} = 0.816

E s c a p e v e l o c i t y o f p l a n e t X i s

v_{x} = 0.816 v_{e a r t h} = 0.816 \times 11.2 = 9.1 k m / s

Commented by Tawakalitu ayo mi last updated on 05/Feb/17

God bless you sir .