Question Number 6648 by Tawakalitu. last updated on 07/Jul/16
$${What}\:{mass}\:{of}\:{ice}\:{at}\:\:−\mathrm{14}\:{will}\:{be}\:{needed}\:{to}\:{cool}\:\mathrm{200}\:{cm}^{\mathrm{3}} \:{of} \\ $$$${an}\:{orange}\:{drink}\:\left({essentially}\:{water}\right)\:{from}\:\mathrm{25}°{C}\:\:{to}\:\:\mathrm{10}°{C} \\ $$$$\left({specific}\:{latent}\:{heat}\:{of}\:{fusion}\:{of}\:{ice}\:=\:\mathrm{3}.\mathrm{36}\:×\:\mathrm{10}^{\mathrm{5}} \:{jkg}^{−\mathrm{1}} \right. \\ $$$${specific}\:{heat}\:{capacity}\:{of}\:{ice}\:=\:\mathrm{2100}\:{jkg}^{−\mathrm{1}} {k}^{−\mathrm{1}} \\ $$$${specific}\:{heat}\:{capacity}\:{of}\:{water}\:=\:\mathrm{4200}\:{jkg}^{−\mathrm{1}} {k}^{−\mathrm{1}} . \\ $$