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Question Number 141937 by cesarL last updated on 24/May/21

W r i t e a n d g r a p h t h e e q u a t i o n o f t h e g r a p h o f y = s i n (π x)

I t i s s t r e t c h e d u p b y a f a c t o r o f 5 a n d s h i f t e d \frac{1}{2} u n i t t o t h e r i g h t

H e l p m e p l e a s e

Commented by MJS_new last updated on 25/May/21

y = f (x)

shift d to the left y = f (x + d)

shift d to the right y = f (x - d)

shift d up y = f (x) + d

shift d down y = f (x) - d

stretch by d horizontally y = d \times f (x)

stretch by d vertically y = f (\frac{x}{d})

“ stretch {up}^{″} seems to mean stretch vertically

\Rightarrow

y = 5 \sin (π (x - \frac{1}{2}))

Commented by cesarL last updated on 25/May/21

t h n k s s i r

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