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Question Number 10129 by Tawakalitu ayo mi last updated on 26/Jan/17
Write in polar form . (1) 3x − y + 5 = 0 (2) x^2 = (√(x^2 + y^2 ))
Writeinpolarform.(1)3x−y+5=0(2)x2=x2+y2
Answered by icyfalcon999 last updated on 26/Jan/17
(1): 3(r cos θ)−(r sin θ)+5=0 3r cos θ−r sin θ=−5 r(3cos θ−sin θ)=−5 ((r(3 cos θ−sin θ))/(3 cos θ−sin θ))=((−5)/(3 cos θ−sin θ)) r=(5/(sin θ−3cos θ)) (2): x^2 =(√(x^2 +y^2 )) (rcos θ)^2 =r r^2 cos^2 θ=r ((r^2 cos^2 θ )/r)=(r/r) r cos^2 θ =1 ((r cos^2 θ )/(cos^2 θ ))=(1/(cos^2 θ)) r=(1/(cos^2 θ )) r=sec^2 θ
(1):3(rcosθ)−(rsinθ)+5=03rcosθ−rsinθ=−5r(3cosθ−sinθ)=−5r(3cosθ−sinθ)3cosθ−sinθ=−53cosθ−sinθr=5sinθ−3cosθ(2):x2=x2+y2(rcosθ)2=rr2cos2θ=rr2cos2θr=rrrcos2θ=1rcos2θcos2θ=1cos2θr=1cos2θr=sec2θ
Commented by Tawakalitu ayo mi last updated on 26/Jan/17
God bless you sir.
Godblessyousir.

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