Write-k-0-n-2-3-k-in-terms-of-n-Where-n-N-

Question Number 135642 by Raxreedoroid last updated on 14/Mar/21

Write \underset{k = 0}{\sum^{n - 2}} 3^{k} in terms of n . Where n \in N .

Answered by Ñï= last updated on 14/Mar/21

\underset{k = 0}{\sum^{n - 2}} 3^{k} = 1 + 3 + 3^{2} + \dots + 3^{n - 2} = \frac{3^{n - 1} - 1}{3 - 1} = \frac{1}{2} (3^{n - 1} - 1)

Answered by Olaf last updated on 14/Mar/21

\underset{k = 0}{\sum^{n - 2}} 3^{k} = 3^{0} \times \frac{1 - 3^{n - 1}}{1 - 3} = \frac{1}{2} (3^{n - 1} - 1)

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