x-1-2-ln-1-1-x-x-dx- Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 135646 by metamorfose last updated on 14/Mar/21 ∫(x+12)ln(1+1x)−xdx=…? Answered by Ñï= last updated on 15/Mar/21 ∫[(x+12)ln(1+1x)−x]dx=∫[(x+12)(ln(x+1)−lnx)−x]dx=∫(x+12)ln(x+1)dx−∫(x+12)lnxdx−∫xdx=(12x2+12x)ln(x+1)−∫x+1−12x+1dx−(12x2+12x)lnx+∫x+12xdx−12x2=(12x2+12x)ln(1+1x)+12ln(x2+x)−12x2+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: if-m-3-2p-3-3mn-a-3-b-3-p-3-and-a-2-b-2-n-then-prove-that-a-b-m-Next Next post: 1-1-2pi-2-2-1-1-pi-2-2-1-1-1-pi-2-2-1-1-2pi-2-2-csc-2-1-pi-pi-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.