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Question Number 137590 by Ñï= last updated on 04/Apr/21

x = 1 + \frac{π + {(π + 1)}^{2} + {(π + 2)}^{3} + {(π + 3)}^{4}}{4 + 5^{2} + 6^{3} + 7^{4}}

\sqrt{x + 2 \sqrt{x - 1}} + \sqrt{x - 2 \sqrt{x - 1}} = ?

Commented by mindispower last updated on 04/Apr/21

\sqrt{x + 2 \sqrt{x - 1}} = \sqrt{{(\sqrt{x - 1} + 1)}^{2}} = 1 + \sqrt{x - 1}

\sqrt{x - 2 \sqrt{x - 1}} = \sqrt{{(\sqrt{x - 1} - 1)}^{2}} 1 - \sqrt{x - 1}

1 < x < 2

w e g e t 2