Question Number 96 by sudhanshur last updated on 25/Jan/15
$${x}=\mathrm{17}^{\mathrm{4}} \:\mathrm{and}\:{y}=\mathrm{14}×\mathrm{16}×\mathrm{18}×\mathrm{20}\:\mathrm{then} \\ $$$$\mathrm{which}\:\mathrm{is}\:\mathrm{greater}? \\ $$
Answered by anoopsingh7374@gmail.com last updated on 27/Nov/14
$$ \\ $$
Commented by 123456 last updated on 13/Dec/14
$${pu} \\ $$$${dim} \\ $$
Answered by ssahoo last updated on 28/Nov/14
$${x}=\mathrm{17}^{\mathrm{4}} \\ $$$${y}=\left(\mathrm{17}−\mathrm{3}\right)\left(\mathrm{17}−\mathrm{1}\right)\left(\mathrm{17}+\mathrm{1}\right)\left(\mathrm{17}+\mathrm{3}\right) \\ $$$$=\left(\mathrm{17}^{\mathrm{2}} −\mathrm{9}\right)\left(\mathrm{17}^{\mathrm{2}} −\mathrm{1}\right) \\ $$$${so}\:{x}>{y} \\ $$