x-199996-x-2-8x-a10-b-c-a-b-c-

Question Number 9987 by konen last updated on 20/Jan/17

x = 199996

x^{2} + 8 x = {a 10}^{b} - c

\Rightarrow a + b + c = ?

Answered by ridwan balatif last updated on 20/Jan/17

x^{2} + 8 x = a \times 10^{b} - c

{(x + 4)}^{2} - 16 = a \times 10^{b} - c

{(199996 + 4)}^{2} - 16 = a \times 10^{b} - c

{(2 \times 10^{5})}^{2} - 16 = a \times 10^{b} - c

4 \times 10^{10} - 16 = a \times 10^{b} - c

a = 4, b = 10, c = 16

a + b + c = 4 + 10 + 16 = 30