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x-2-2x-3-0-




Question Number 140225 by mondli last updated on 05/May/21
x^2 +2x+3=0
$${x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{3}=\mathrm{0}\:\: \\ $$
Answered by MJS_new last updated on 05/May/21
x^2 +px+q=0 ⇒ x=−(p/2)±(√((p^2 /4)−q))
$${x}^{\mathrm{2}} +{px}+{q}=\mathrm{0}\:\Rightarrow\:{x}=−\frac{{p}}{\mathrm{2}}\pm\sqrt{\frac{{p}^{\mathrm{2}} }{\mathrm{4}}−{q}} \\ $$

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