Question Number 135259 by leena12345 last updated on 11/Mar/21
$$\int\left({x}^{\mathrm{2}} +\mathrm{3}{x}\right)\mathrm{cos}\:\left({x}\right){dx} \\ $$
Answered by Ar Brandon last updated on 11/Mar/21
$$\mathcal{I}=\int\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}\right)\mathrm{cosxdx} \\ $$$$\:\:\:=\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}\right)\mathrm{sinx}−\int\left(\mathrm{2x}+\mathrm{3}\right)\mathrm{sinxdx} \\ $$$$\:\:\:=\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}\right)\mathrm{sinx}+\left(\mathrm{2x}+\mathrm{3}\right)\mathrm{cosx}−\int\mathrm{2cosxdx} \\ $$$$\:\:\:=\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}\right)\mathrm{sinx}+\left(\mathrm{2x}+\mathrm{3}\right)\mathrm{cosx}−\mathrm{2sinx}+\mathcal{C} \\ $$
Answered by Ar Brandon last updated on 11/Mar/21
Commented by Dwaipayan Shikari last updated on 11/Mar/21
$${LaTeX}? \\ $$
Commented by Ar Brandon last updated on 11/Mar/21
Yeah ��