Question Number 4674 by thachan last updated on 20/Feb/16
$${x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{2}=\mathrm{0} \\ $$
Answered by FilupSmith last updated on 20/Feb/16
$${x}=\frac{−{b}\pm\sqrt{{b}^{\mathrm{2}} −\mathrm{4}{ac}}}{\mathrm{2}{a}} \\ $$$${x}=\frac{−\mathrm{5}\pm\sqrt{\mathrm{25}−\mathrm{4}\left(\mathrm{1}\right)\left(\mathrm{2}\right)}}{\mathrm{2}\left(\mathrm{1}\right)} \\ $$$${x}=\frac{−\mathrm{5}\pm\sqrt{\mathrm{17}}}{\mathrm{2}} \\ $$