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x-2-816-64-77-x-write-x-like-a-c-b-d-




Question Number 8351 by Nayon last updated on 09/Oct/16
     x^2 =816−64(√(77))     x=?[write x like a(√(c ))+b(√d])
x2=8166477x=?[writexlikeac+bd]
Commented by ridwan balatif last updated on 09/Oct/16
x=±(√(816−2×32(√(77))))  x=±(√(816−2(√(32^2 ×77))))  x=±(√(816−2(√(78848))))  x=±(√((704+112)−2(√(704×112))))  x=±((√(704))−(√(112)))  x=±(8(√(11))−4(√7))  x=±4(2(√(11))−(√7))
x=±8162×3277x=±8162322×77x=±816278848x=±(704+112)2704×112x=±(704112)x=±(81147)x=±4(2117)
Answered by Rasheed Soomro last updated on 09/Oct/16
Let(a(√(c ))+b(√d))^2 = 816−64(√(77))      a,b,c,d∈N       (a(√c))^2 +2(a(√c))(b(√d))+(b(√d))^2 =816−64(√(77))       a^2 c+2ab(√(cd))+b^2 d=816−64(√(77))  Comparing          a^2 c+b^2 d=816  ∧  2ab=64  ∧ cd=77  cd=77=7×11⇒  Let c=7 , d=11   a^2 c+b^2 d=816⇒7a^2 +11b^2 =816  2ab=64⇒b=32/a  7a^2 +11b^2 =816⇒7a^2 +11(32/a)^2 =816  7a^2 +11(1024/a^2 )=816  7a^2 +11264/a^2 =816  7a^4 −816a^2 +11264=0  a^2 =((−(−816)±(√((−816)^2 −4(7)(11264))))/(2(7)))  Taking + out of ± we will get a fractional  number, which is against our assumption.  Hence we will take − sign out of ±.  a^2 =((816−(√((−816)^2 −4(7)(11264))))/(14))=((816−592)/(14))=16  a=±4⇒b=32/a=32/±4=±8  a(√(c ))+b(√d)=(±4)(√7)±8(√(11))=±4((√7)+2(√(11)))
Let(ac+bd)2=8166477a,b,c,dN(ac)2+2(ac)(bd)+(bd)2=8166477a2c+2abcd+b2d=8166477Comparinga2c+b2d=8162ab=64cd=77cd=77=7×11Letc=7,d=11a2c+b2d=8167a2+11b2=8162ab=64b=32/a7a2+11b2=8167a2+11(32/a)2=8167a2+11(1024/a2)=8167a2+11264/a2=8167a4816a2+11264=0a2=(816)±(816)24(7)(11264)2(7)Taking+outof±wewillgetafractionalnumber,whichisagainstourassumption.Hencewewilltakesignoutof±.a2=816(816)24(7)(11264)14=81659214=16a=±4b=32/a=32/±4=±8ac+bd=(±4)7±811=±4(7+211)

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