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x-2-cos-x-2-dx-




Question Number 141333 by cesarL last updated on 17/May/21
∫x^2 cos ((x/2))dx
x2cos(x2)dx
Answered by qaz last updated on 17/May/21
∫x^2 cos (x/2)dx  =2x^2 sin (x/2)−4∫xsin (x/2)dx  =2x^2 sin(x/2) −4(−2xcos (x/2)+2∫cos (x/2)dx)  =2x^2 sin (x/2)+8xcos (x/2)−16sin (x/2)+C
x2cosx2dx=2x2sinx24xsinx2dx=2x2sinx24(2xcosx2+2cosx2dx)=2x2sinx2+8xcosx216sinx2+C
Commented by cesarL last updated on 17/May/21
Thank you bro
Thankyoubro

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