x-2-x-12-x-15-k-x-16-find-x-in-terms-of-k-gt-0-

Question Number 141663 by ajfour last updated on 22/May/21

\underset{- - - - - - - - - - - - - - - - - - -}{}

x^{2} (x - 12) (x - 15) = k (x - 16)

f i n d x i n t e r m s o f k (> 0) .

\overset{- - - - - - - - - - - - - - - - - - -}{}

Commented by Rasheed.Sindhi last updated on 22/May/21

\frac{x^{2} (x - 12) (x - 15)}{x - 16} = k

k > 0 \Rightarrow x ≰ 12 \land 15 ≰ x ≰ 16

\Rightarrow x \in (12, 15) \cup (16, \infty)