Question Number 7785 by B last updated on 15/Sep/16
$${x}^{\mathrm{2}} −{x}^{\mathrm{2}} ={x}^{\mathrm{2}} −{x}^{\mathrm{2}} \\ $$$$\left({x}−{x}\right)\left({x}+{x}\right)={x}\left({x}−{x}\right) \\ $$$${x}−{x}={x} \\ $$$$\mathrm{2}{x}={x} \\ $$$$\mathrm{2}=\mathrm{1} \\ $$
Commented by Chantria last updated on 15/Sep/16
$${x}−{x}\:=\:\mathrm{0}\:{we}\:{can}'{t}\:{divide}\:{it} \\ $$$$ \\ $$