Question Number 68315 by 9102176137086 last updated on 08/Sep/19
$$\int\left(\frac{{x}^{−\mathrm{3}} +\mathrm{2}{x}−\mathrm{4}}{{x}}\right) \\ $$
Commented by mathmax by abdo last updated on 10/Sep/19
$$=\int\:\left({x}^{−\mathrm{4}} \:+\mathrm{2}\:−\frac{\mathrm{4}}{{x}}\right){dx}\:=\frac{\mathrm{1}}{−\mathrm{4}+\mathrm{1}}{x}^{−\mathrm{4}+\mathrm{1}} \:+\mathrm{2}{x}−\mathrm{4}{ln}\mid{x}\mid\:+{c} \\ $$$$=−\frac{\mathrm{1}}{\mathrm{3}{x}^{\mathrm{3}} }\:+\mathrm{2}{x}−\mathrm{4}{ln}\mid{x}\mid\:+{c} \\ $$