Question Number 66863 by ajfour last updated on 20/Aug/19
$$\:\:\:{x}^{\mathrm{3}} \left({b}−{x}\right)^{\mathrm{2}} +{aex}\left({x}−{b}\right)+{e}^{\mathrm{2}} =\mathrm{0}\: \\ $$$${solve}\:{for}\:{x}. \\ $$
x-3-b-x-2-aex-x-b-e-2-0-solve-for-x-