Question Number 10124 by konen last updated on 25/Jan/17
$$\mathrm{x}=\mathrm{4}^{\left(−\mathrm{2}\right)^{−\mathrm{1}} } \\ $$$$\mathrm{y}=\left(\mathrm{0}.\mathrm{4}\right)^{−\mathrm{2}} \\ $$$$\Rightarrow\:\mathrm{2x}+\mathrm{4y}=? \\ $$
Answered by FilupSmith last updated on 25/Jan/17
$${x}=\mathrm{4}^{\left(−\mathrm{2}\right)^{−\mathrm{1}} } =\mathrm{4}^{\frac{\mathrm{1}}{−\mathrm{2}}} =\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${y}=\mathrm{0}.\mathrm{4}^{−\mathrm{2}} =\left(\frac{\mathrm{2}}{\mathrm{5}}\right)^{−\mathrm{2}} =\frac{\mathrm{25}}{\mathrm{4}} \\ $$$$\mathrm{2}{x}+\mathrm{4}{y}=\mathrm{2}\left(\frac{\mathrm{1}}{\mathrm{2}}\right)+\mathrm{4}\left(\frac{\mathrm{25}}{\mathrm{4}}\right)=\mathrm{1}+\mathrm{25}=\mathrm{26} \\ $$$$ \\ $$$$\mathrm{2}{x}+\mathrm{4}{y}=\mathrm{26} \\ $$