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Question Number 7392 by Tawakalitu. last updated on 26/Aug/16
(√x) + 5 + (√x) + 5 = tanΘ find the value of Θ
$$\sqrt{{x}}\:+\:\mathrm{5}\:+\:\sqrt{{x}}\:+\:\mathrm{5}\:=\:{tan}\Theta \\ $$$$ \\ $$$${find}\:{the}\:{value}\:{of}\:\Theta \\ $$
Commented by Yozzia last updated on 26/Aug/16
general solution, Θ=nπ+tan^(−1) (2(√x)+10), n∈Z.
$${general}\:{solution},\:\Theta={n}\pi+{tan}^{−\mathrm{1}} \left(\mathrm{2}\sqrt{{x}}+\mathrm{10}\right),\:{n}\in\mathbb{Z}. \\ $$
Commented by Rasheed Soomro last updated on 26/Aug/16
2(√x)+10=tan Θ Θ=tan^(−1) (2(√x)+10)
$$\mathrm{2}\sqrt{{x}}+\mathrm{10}=\mathrm{tan}\:\Theta \\ $$$$\Theta=\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{2}\sqrt{{x}}+\mathrm{10}\right) \\ $$$$ \\ $$
Commented by Tawakalitu. last updated on 26/Aug/16
I really appreciate, God bless you.
$${I}\:{really}\:{appreciate},\:{God}\:{bless}\:{you}. \\ $$

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