Question Number 8914 by tawakalitu last updated on 04/Nov/16
$$\int\:\mid\mathrm{x}\mid\:\mathrm{dx} \\ $$
Commented by 123456 last updated on 05/Nov/16
$${I}=\int\mid{x}\mid{dx} \\ $$$${x}>\mathrm{0} \\ $$$${I}=\int{xdx}=\frac{{x}^{\mathrm{2}} }{\mathrm{2}}+{C} \\ $$$${x}<\mathrm{0} \\ $$$${I}=−\int{xdx}=−\frac{{x}^{\mathrm{2}} }{\mathrm{2}}+{C} \\ $$$$\int\mid{x}\mid{dx}=\frac{\mathrm{sign}\left({x}\right){x}^{\mathrm{2}} }{\mathrm{2}}+{C} \\ $$
Commented by tawakalitu last updated on 05/Nov/16
$$\mathrm{Thanks}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$