Question Number 142730 by Gbenga last updated on 04/Jun/21
$${x}^{{x}^{\mathrm{30}} } =\sqrt{}\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}} \\ $$
Commented by mr W last updated on 04/Jun/21
$${x}=\sqrt[{\mathrm{30}}]{\frac{\mathrm{15ln}\:\mathrm{2}}{\mathrm{2}{W}\left(\frac{\mathrm{15ln}\:\mathrm{2}}{\mathrm{2}}\right)}}\approx\mathrm{1}.\mathrm{045993524} \\ $$