Question Number 66173 by Tony Lin last updated on 10/Aug/19
$${x}^{{x}^{{x}\centerdot^{.^{.{x}} } } } =\mathrm{2} \\ $$$${x}=? \\ $$
Answered by mr W last updated on 10/Aug/19
$${x}>\mathrm{0} \\ $$$${x}^{\mathrm{2}} =\mathrm{2} \\ $$$${x}=\sqrt{\mathrm{2}} \\ $$