Question Number 140525 by mathdanisur last updated on 09/May/21
$${x};{y};{z}>\mathrm{0}\:;\:{x}+{y}+{z}=\mathrm{3} \\ $$$${proof}\:\left({x}^{\mathrm{3}} +\mathrm{2}\right)\left({y}^{\mathrm{3}} +\mathrm{2}\right)\left({z}^{\mathrm{3}} +\mathrm{2}\right)\geqslant\mathrm{3}^{\mathrm{3}} \\ $$
Answered by mitica last updated on 09/May/21
$${jensen} \\ $$
Answered by mitica last updated on 09/May/21
Commented by mathdanisur last updated on 10/May/21
$${thanks}\:{sir} \\ $$