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y-2-x-2-5-y-x-2-Find-x-y-




Question Number 137982 by mey3nipaba last updated on 08/Apr/21
y^2 −x^2 =5(y−x)^2 . Find x:y
y2x2=5(yx)2.Findx:y
Commented by mey3nipaba last updated on 08/Apr/21
please help
pleasehelp
Answered by Dwaipayan Shikari last updated on 08/Apr/21
((y^2 −x^2 )/((y−x)^2 ))=5⇒(((y−x)(y+x))/((y−x)(y−x)))=5  ⇒((y+x)/(y−x))=5⇒((y+x+(y−x))/(y+x−(y−x)))=((5+1)/(5−1))⇒(y/x)=(6/4)    ⇒(x/y)=(2/3)
y2x2(yx)2=5(yx)(y+x)(yx)(yx)=5y+xyx=5y+x+(yx)y+x(yx)=5+151yx=64xy=23
Commented by mey3nipaba last updated on 08/Apr/21
thanks so much. i had the answer but wanted to confirm
thankssomuch.ihadtheanswerbutwantedtoconfirm
Answered by Rasheed.Sindhi last updated on 08/Apr/21
An Alternate Way  (x/y)=k⇒x=yk  y^2 −x^2 =5(y−x)^2   ⇒y^2 −(yk)^2 =5(y−yk)^2       y^2 (1−k^2 )=5y^2 (1−k)^2       y^2 (1−k)(1+k)−5y^2 (1−k)^2 =0     (1−k)( y^2 (1+k)−5y^2 (1−k) )=0      k=1 ∣  y^2 (1+k)=5y^2 (1−k)     x:y=1:1  ∣ ((1+k)/(1−k))=((5y^2 )/y^2 )=5                        ∣   1+k=5−5k                        ∣    6k=4⇒k=2/3                        ∣    x:y=2:3
AnAlternateWayxy=kx=yky2x2=5(yx)2y2(yk)2=5(yyk)2y2(1k2)=5y2(1k)2y2(1k)(1+k)5y2(1k)2=0(1k)(y2(1+k)5y2(1k))=0k=1y2(1+k)=5y2(1k)x:y=1:11+k1k=5y2y2=51+k=55k6k=4k=2/3x:y=2:3
Answered by nadovic last updated on 08/Apr/21
y^2  − x^2  = 5y^2  − 10xy + 5x^2   6x^2  − 10xy + 4y^2  = 0  2(3x^2  − 5xy + 2y^2 ) = 0  2(x − y)(3x − 2y) = 0  (x/y) = 1  or  (x/y) = (2/3)  x:y = 1:1   or   x:y = 2:3
y2x2=5y210xy+5x26x210xy+4y2=02(3x25xy+2y2)=02(xy)(3x2y)=0xy=1orxy=23x:y=1:1orx:y=2:3
Answered by Rasheed.Sindhi last updated on 09/Apr/21
y^2 −x^2 =5(y−x)^2 . Find x:y  y^2 (1−(x^2 /y^2 ))=5y^2 (1−(x/y))^2   y≠0⇒(1−(x^2 /y^2 ))=5(1−(x/y))^2     (x/y)=u⇒(1−u^2 )=5(1−u)^2   (1−u)(1+u)−5(1−u)^2 =0  (1−u)(1+u−5+5u)=0  (1−u)(6u−4)=0  u=1 ∣  u=(2/3)  x:y=1:1  ∣  x:y=2:3
y2x2=5(yx)2.Findx:yy2(1x2y2)=5y2(1xy)2y0(1x2y2)=5(1xy)2xy=u(1u2)=5(1u)2(1u)(1+u)5(1u)2=0(1u)(1+u5+5u)=0(1u)(6u4)=0u=1u=23x:y=1:1x:y=2:3
Answered by MJS_new last updated on 09/Apr/21
(y−x)(y+x)=5(y−x)^2   (1) y−x=0  ⇒ (x/y)=1  (2) y+x=5(y−x) ⇒ (x/y)=(2/3)
(yx)(y+x)=5(yx)2(1)yx=0xy=1(2)y+x=5(yx)xy=23

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