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y-5sin-2000pit-0-4x-calculate-the-wavelength-




Question Number 10713 by Saham last updated on 23/Feb/17
y = 5sin(2000πt − 0.4x), calculate the wavelength
y=5sin(2000πt0.4x),calculatethewavelength
Answered by ridwan balatif last updated on 23/Feb/17
y=5sin(2000πt−0.4x)  base formula′s y=Asin(ωt−kx)  A=5  ω=2000π  k=0.4  ((2π)/λ)=(2/5)  λ=5π →wavelength
y=5sin(2000πt0.4x)baseformulasy=Asin(ωtkx)A=5ω=2000πk=0.42πλ=25λ=5πwavelength
Commented by Saham last updated on 23/Feb/17
God bless you sir.
Godblessyousir.
Answered by mrW1 last updated on 23/Feb/17
A=5 m  ω=2000π  k=0.4  frequency f=(ω/(2π))=((2000π)/(2π))=1000 Hz  wave length λ=((2π)/k)=((2π)/(0.4))=5π=15.7 m  wave speed v=λf=15.7×1000=15700 m/s
A=5mω=2000πk=0.4frequencyf=ω2π=2000π2π=1000Hzwavelengthλ=2πk=2π0.4=5π=15.7mwavespeedv=λf=15.7×1000=15700m/s
Commented by Saham last updated on 23/Feb/17
God bless you sir.
Godblessyousir.

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