y-x-2-4x-9-x-2-4x-5-the-values-of-the-feture-set-of-prime-numbers-

Question Number 12632 by @ANTARES_VY last updated on 27/Apr/17

y = \frac{x^{2} - 4 x + 9}{x^{2} - 4 x + 5} the values of the

feture set of prime numbers ?

Answered by abcd last updated on 27/Apr/17

Commented by prakash jain last updated on 28/Apr/17

There is a mistake in calculation

of determinant above .

Discriminant

D = b^{2} - 4 a c

= 4^{2} {(y - 1)}^{2} - 4 (y - 1) (5 y - 9)

= 4 (y - 1) (- y + 5)

= - 4 (y - 1) (y - 5)

D ⩾ 0 \Rightarrow 1 ⩽ y ⩽ 5

y = 1 is not possible original

function except in limiting case

of x \to \infty

1 < y ⩽ 5