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y-x-2-bx-c-x-1-point-function-accepts-a-maximum-value-equal-to-5-Find-y-1-




Question Number 12596 by @ANTARES_VY last updated on 26/Apr/17
y=−x^2 +bx+c      x=−1  point  function  accepts   a  maximum  value  equal  to  5.  Find  y(1).
y=x2+bx+cx=1pointfunctionacceptsamaximumvalueequalto5.Findy(1).
Answered by ajfour last updated on 26/Apr/17
y=c−[(x−(b/2))^2 −(b^2 /4)]  has maximum at x=(b/2)  so (b/2)=−1  ⇒ b=−2   the maximum value being    c+(b^2 /4) =5 ⇒ c=5−(b^2 /4)= 5−(4/4)=4  y= −x^2 −2x+4 =5−(x+1)^2   y(1)=−1+b+c = −1−2+4=1 .
y=c[(xb2)2b24]hasmaximumatx=b2sob2=1b=2themaximumvaluebeingc+b24=5c=5b24=544=4y=x22x+4=5(x+1)2y(1)=1+b+c=12+4=1.
Commented by @ANTARES_VY last updated on 26/Apr/17
error  answer
erroranswer
Commented by ajfour last updated on 26/Apr/17
now ?
now?
Commented by @ANTARES_VY last updated on 26/Apr/17
The  answer  should  be  1.
Theanswershouldbe1.
Commented by @ANTARES_VY last updated on 26/Apr/17
A  series  please
Aseriesplease

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