z-999-1-z-2-1-z-2-z-1-find-the-sum-of-the-coefficientes-of-the-polynomial-obtained-bh-dividing-the-expression-by-the-polynomial-

Question Number 140709 by mathdanisur last updated on 11/May/21

\frac{z^{999} - 1}{(z^{2} + 1) \cdot (z^{2} + z + 1)}

f i n d t h e s u m o f t h e c o e f f i c i e n t e s o f

t h e p o l y n o m i a l o b t a i n e d b h d i v i d i n g

t h e e x p r e s s i o n b y t h e p o l y n o m i a l \dots

Commented by mr W last updated on 11/May/21

s u m = 0

Commented by mathdanisur last updated on 11/May/21

S i r, s o l u t i o n p l e a s e . .

Commented by mr W last updated on 11/May/21

i f f (z) = a_{0} + a_{1} z + a_{2} z^{2} + \dots + a_{n} z^{n}

\Rightarrow f (1) = a_{0} + a_{1} + a_{2} + \dots + a_{n} = s u m o f

c o e f f i c i e n t s .

i n c u r r e n t c a s e

f (z) = \frac{z^{999} - 1}{\dots .}

f (1) = \frac{1^{999} - 1}{\dots .} = 0 = s u m o f a l l c o e f .

Commented by mathdanisur last updated on 12/May/21

c o o l S i r t h a k y o u