Menu Close

z-z-why-




Question Number 139483 by qaz last updated on 27/Apr/21
Γ(z^− )=Γ(z)^(−)     why?
$$\Gamma\left(\overset{−} {{z}}\right)=\overline {\Gamma\left({z}\right)}\:\:\:\:{why}? \\ $$
Answered by mnjuly1970 last updated on 27/Apr/21
  hint    Γ(z)=e^(−γz) (1/z) Π_(k=1) ^∞ ((e^(z/k)   )/(1+(z/k)))   z→z^−  ......
$$\:\:{hint} \\ $$$$\:\:\Gamma\left({z}\right)={e}^{−\gamma{z}} \frac{\mathrm{1}}{{z}}\:\underset{{k}=\mathrm{1}} {\overset{\infty} {\prod}}\frac{{e}^{\frac{{z}}{{k}}} \:\:}{\mathrm{1}+\frac{{z}}{{k}}} \\ $$$$\:{z}\rightarrow\overset{−} {{z}}\:…… \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *