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Question Number 130605 by Study last updated on 27/Jan/21
0^0 =??
$$\mathrm{0}^{\mathrm{0}} =?? \\ $$
Answered by mathmax by abdo last updated on 27/Jan/21
lim_(x→0^+ )  x^x  =lim_(x→0^+ )   e^(xlnx)  =e^0  =1
$$\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{0}^{+} } \:\mathrm{x}^{\mathrm{x}} \:=\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{0}^{+} } \:\:\mathrm{e}^{\mathrm{xlnx}} \:=\mathrm{e}^{\mathrm{0}} \:=\mathrm{1} \\ $$
Answered by 0731619177 last updated on 30/Jan/21
$$ \\ $$

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