0-1-2x-2-x-2-1-2-dx-

Question Number 154926 by physicstutes last updated on 23/Sep/21

\int_{0}^{1} \frac{2 x^{2}}{{(x^{2} + 1)}^{2}} d x =

Answered by qaz last updated on 23/Sep/21

\int_{0}^{1} \frac{{2 x}^{2}}{{(x^{2} + 1)}^{2}} dx

= {\int xd (- \frac{1}{x^{2} + 1})}_{0}^{1}

= {- \frac{x}{x^{2} + 1} + \int \frac{dx}{x^{2} + 1}}_{0}^{1}

= - \frac{1}{2} + \frac{π}{4}

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