0-1-e-x-2-dx-correct-to-3-decimal-place-

Question Number 56061 by necx1 last updated on 09/Mar/19

\int_{0}^{1} e^{- x^{2}} d x c o r r e c t t o 3 d e c i m a l p l a c e .

Answered by tanmay.chaudhury50@gmail.com last updated on 09/Mar/19

\int_{0}^{1} (1 - x^{2} + \frac{x^{4}}{2!} - \frac{x^{6}}{3!} + \frac{x^{8}}{4!} - \dots) d x

∣ x - \frac{x^{3}}{3} + \frac{x^{5}}{10} - \frac{x^{7}}{42} + \frac{x^{9}}{216} ∣_{0}^{1}

= \frac{1}{1} - \frac{1}{3} + \frac{1}{10} - \frac{1}{42} + \frac{1}{216}

= 1 + 0.1 + 0.0046 - 0.33 - 0.0238

1.1046 - 0.3538

\approx> . 7508

Commented by tanmay.chaudhury50@gmail.com last updated on 09/Mar/19

Commented by necx1 last updated on 09/Mar/19

t h a n k y o u s o m u c h .

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