0-1-ln-ln-1-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 158697 by amin96 last updated on 07/Nov/21 ∫01ln(ln(1−x))dx=? Answered by mnjuly1970 last updated on 08/Nov/21 1−x=uΩ=Re{∫01ln(ln(u))du}=−ln(u)=t=Re(∫0∞e−tln(−t)dt)=Re(∫0∞e−t(ln(eiπ)+ln(t))dt)=Re(∫0∞e−t(iπ+ln(t))dt)=∫0∞e−t(ln(t))dt=−γγ:euler−mascheruniconstant Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: log-3-3-3x-log-x-3-3x-log-3-x-3-log-3-3-x-3-log-x-3-x-3-log-3-x-3-2-please-i-need-help-Ive-been-trying-but-still-not-getting-answer-Next Next post: Question-158700 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.