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0-1-log-2-x-1-x-dx-




Question Number 156213 by MathSh last updated on 09/Oct/21
Ω =∫_0 ^1  log^2  (((Γ(x+1))/x)) dx = ?
$$\Omega\:=\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\mathrm{log}^{\mathrm{2}} \:\left(\frac{\Gamma\left(\mathrm{x}+\mathrm{1}\right)}{\mathrm{x}}\right)\:\mathrm{dx}\:=\:? \\ $$

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