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0-1-x-4035-x-4-1-2017-3x-1-4-dx-




Question Number 96595 by Tony Lin last updated on 03/Jun/20
∫_0 ^1 x^(4035) (x^4 +1)^(2017) (3x+1)^4 dx
$$\int_{\mathrm{0}} ^{\mathrm{1}} {x}^{\mathrm{4035}} \left({x}^{\mathrm{4}} +\mathrm{1}\right)^{\mathrm{2017}} \left(\mathrm{3}{x}+\mathrm{1}\right)^{\mathrm{4}} {dx} \\ $$

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