0-1-x-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 96990 by Ar Brandon last updated on 06/Jun/20 ∫01(x)xdx Answered by Sourav mridha last updated on 06/Jun/20 ∫01ex2.ln(x)dx=∑∞n=012n∫0∞xn2.[ln(x)]nn!dxnowletln(x)=−ksoweget=∑∞n=0(−1)n2nn!∫0∞e−(n2+1)k.kndk=∑∞n=0(−1)n2nΓ(n+1).Γ(n+1)(n2+1)n+1.[usingLaplacetransform=2∑∞n=0(−1)n(n+2)n+1. Commented by Ar Brandon last updated on 12/Jun/20 ��thanks Commented by smridha last updated on 12/Jun/20 welcome Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Find-0-x-cos-x-1-sin-x-2-dx-Next Next post: 0-x-x-2-4x-4- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.