Menu Close

0-2pi-acos-bcos-d-a-2-b-2-2abcos-3-2-




Question Number 39272 by ajfour last updated on 04/Jul/18
∫_0 ^(  2π) (((acos α−bcos θ)dθ)/([a^2 +b^2 −2abcos (θ−α)]^(3/2) )) = ?
$$\int_{\mathrm{0}} ^{\:\:\mathrm{2}\pi} \frac{\left({a}\mathrm{cos}\:\alpha−{b}\mathrm{cos}\:\theta\right){d}\theta}{\left[{a}^{\mathrm{2}} +{b}^{\mathrm{2}} −\mathrm{2}{ab}\mathrm{cos}\:\left(\theta−\alpha\right)\right]^{\mathrm{3}/\mathrm{2}} }\:=\:? \\ $$
Commented by ajfour last updated on 06/Jul/18
please consider..
$${please}\:{consider}.. \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *