Question Number 26463 by sanyam soni last updated on 25/Dec/17
$$\int_{\mathrm{0}} ^{\mathrm{2}\pi} \mathrm{cos}^{\mathrm{2}} \theta\mathrm{sin}\:\theta{d}\theta \\ $$
Commented by abdo imad last updated on 25/Dec/17
$$\left.=\:−\frac{\mathrm{1}}{\mathrm{3}}{cos}_{\theta} ^{\mathrm{3}} \:\right]_{\theta=\mathrm{0}} ^{\theta=\mathrm{2}\pi} =\:−\frac{\mathrm{1}}{\mathrm{3}}.\mathrm{0}=\mathrm{0} \\ $$