0-a-2-x-2-a-2-x-2-3-2-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 13960 by tawa tawa last updated on 25/May/17 ∫0a2x2(a2−x2)−3/2dx Answered by ajfour last updated on 25/May/17 I=∫0a/2x2(a2−x2)3/2dxletx=asinθ⇒dx=acosθdθwhenx=0,θ=0whenx=a2,θ=π6I=∫0π/6a2sin2θa3cos3θ(acosθdθ)=∫0π/6tan2θdθ=∫0π/6(sec2θ−1)dθ=[tanθ−θ]∣0π/6I=13−π6=(23−π)6. Commented by tawa tawa last updated on 25/May/17 Godblessyousir.iunderstandnow. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: n-1-1-n-1-n-n-n-1-Next Next post: 0-30pi-sin-x-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.