Question Number 151894 by peter frank last updated on 24/Aug/21

Commented by peter frank last updated on 24/Aug/21

Answered by Ar Brandon last updated on 24/Aug/21
![I=∫_0 ^a x(√((a^2 −x^2 )/(a^2 +x^2 )))dx=(1/2)∫_0 ^a^2 (√((a^2 −u)/(a^2 +u)))du =(a^2 /2)∫_0 ^1 (√((1−v)/(1+v)))dv=(a^2 /2)∫_0 ^1 ((1−v)/( (√(1−v^2 ))))dv =(a^2 /2)[arcsin(v)+(√(1−v^2 ))]_0 ^1 =(a^2 /2)((π/2)−1) −a≤x≤a](https://www.tinkutara.com/question/Q151920.png)
Commented by peter frank last updated on 24/Aug/21

Commented by Ar Brandon last updated on 24/Aug/21
