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0-oo-artan-2x-arctan-x-x-dx-




Question Number 184626 by SANOGO last updated on 09/Jan/23
∫_0 ^(+oo)  ((artan(2x)−arctan(x))/x)dx
0+ooartan(2x)arctan(x)xdx
Answered by qaz last updated on 10/Jan/23
∫_0 ^∞ ((arctan 2x−arctan x)/x)dx  =∫_0 ^∞ ∫_1 ^2 (1/(1+a^2 x^2 ))dadx=∫_1 ^2 da∫_0 ^∞ (dx/(1+a^2 x^2 ))  =∫_1 ^2 (π/(2a))da=(π/2)ln2
0arctan2xarctanxxdx=01211+a2x2dadx=12da0dx1+a2x2=12π2ada=π2ln2

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