0-pi-1-a-2-2a-cosx-1-dx-a-lt-1-is- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 101585 by Rohit@Thakur last updated on 03/Jul/20 ∫0π1a2−2acosx+1dx(a<1)is Answered by mathmax by abdo last updated on 03/Jul/20 f(a)=∫0πdxa2−2acosx+1changementtan(x2)=tgivef(a)=∫0∞2dt(1+t2)(a2−2a×1−t21+t2+1)=∫0∞2dta2+a2t2−2a+2at2+1+t2=∫0∞2dt(a2+2a+1)t2+a2−2a+1=2(a+1)2∫0∞dtt2+(a−1)2(a+1)2=2(a+1)2∫0∞dtt2+(a−1a+1)2=t=1−a1+au2(a+1)2∫0∞1(1−a1+a)2(1+u2)×1−a1+adu=2(1+a)2×(1+a)2(1−a)2×1−a1+a∫0∞du1+u2=21−a2×π2=π1−a2⇒f(a)=π1−a2 Commented by Rohit@Thakur last updated on 04/Jul/20 Thankyousir Commented by mathmax by abdo last updated on 04/Jul/20 youarewelcomesir. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-167115Next Next post: Question-167122 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.