0-pi-2-cos-3-x-1-cos-2-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 149903 by bramlexs22 last updated on 08/Aug/21 Ω=∫π20cos3x1−cos2xdx Answered by Ar Brandon last updated on 08/Aug/21 Ω=∫0π2cos3x1−cos2xdx=∫0π21−sin2xsinxcosxdx=∫01(1u−u)du=[lnu−u22]01=−12+∞divergent Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: lim-x-pi-pi-pi-4x-cos-pi-x-1-2-Next Next post: Question-18834 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.