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0-pi-2-dx-sin-x-




Question Number 117216 by bobhans last updated on 10/Oct/20
  ∫_0 ^(π/2) (dx/( (√(sin x)))) =?
π/20dxsinx=?
Answered by TANMAY PANACEA last updated on 10/Oct/20
2∫_0 ^(π/2) sin^(2p−1) xcos^(2q−1) x dx=((⌈(p)⌈(q))/(⌈p+q)))  (1/2)×2∫_0 ^(π/2) (sinx)^(2×(1/4)−1) cos^(2×(1/2)−1) dx  =(1/2)×((⌈((1/4)) ×⌈(1/2))/(⌈((1/4)+(1/2))))
20π2sin2p1xcos2q1xdx=(p)(q)p+q)12×20π2(sinx)2×141cos2×121dx=12×(14)×12(14+12)
Commented by bobhans last updated on 10/Oct/20
this is Γ =  gamma function?
thisisΓ=gammafunction?
Commented by TANMAY PANACEA last updated on 10/Oct/20
yes sir
yessir
Commented by bobhans last updated on 10/Oct/20
thank you sir
thankyousir

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