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0-pi-2-e-2arctg-u-u-




Question Number 147399 by ArielVyny last updated on 20/Jul/21
∫_0 ^(π/2) (e^(2arctg(u)) /( (√u)))
$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{{e}^{\mathrm{2}{arctg}\left({u}\right)} }{\:\sqrt{{u}}} \\ $$

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