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0-pi-2-e-sinx-e-cosx-e-sinx-dx-




Question Number 152420 by tabata last updated on 28/Aug/21
∫_0 ^( (π/2))  (e^(sinx) /(e^(cosx) +e^(sinx) ))dx   ?
0π2esinxecosx+esinxdx?
Answered by mindispower last updated on 28/Aug/21
f(a+b−x)+f(x)=c  ∫_a ^b f(x)dx=(1/2)c(b−a)
f(a+bx)+f(x)=cabf(x)dx=12c(ba)
Answered by Lordose last updated on 28/Aug/21
Ω = ∫_0 ^(𝛑/2) (e^(sin(x)) /(e^(cos(x)) +e^(sin(x)) ))dx    (1)  Ω =^(king′s rule) ∫_0 ^(𝛑/2) (e^(cos(x)) /(e^(cos(x)) +e^(sin(x)) ))dx   (2)  (((1) + (2))/2) ::  Ω = (1/2)∫_0 ^(𝛑/2) 1dx = (𝛑/4)
Ω=0π2esin(x)ecos(x)+esin(x)dx(1)Ω=kingsrule0π2ecos(x)ecos(x)+esin(x)dx(2)(1)+(2)2::Ω=120π21dx=π4

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