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0-pi-2-x-3-sin-2-x-dx-3-8-pi-2-ln-4-7-3-




Question Number 165380 by mnjuly1970 last updated on 31/Jan/22
       ∫_0 ^( (π/2)) (( x^( 3) )/(sin^( 2) (x)))dx=^?  (3/8) (π^( 2) ln(4)−7ζ(3))
0π2x3sin2(x)dx=?38(π2ln(4)7ζ(3))
Answered by Ar Brandon last updated on 31/Jan/22
I=∫_0 ^(π/2) x^3 cosec^2 xdx=−[x^3 cotx]_0 ^(π/2) +3∫_0 ^(π/2) x^2 cotxdx     =3[x^2 ln(sinx)]_0 ^(π/2) −6∫_0 ^(π/2) xln(sin(x)dx
I=0π2x3cosec2xdx=[x3cotx]0π2+30π2x2cotxdx=3[x2ln(sinx)]0π260π2xln(sin(x)dx

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