0-pi-2-x-3-sin-2-x-dx-3-8-pi-2-ln-4-7-3- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 165380 by mnjuly1970 last updated on 31/Jan/22 ∫0π2x3sin2(x)dx=?38(π2ln(4)−7ζ(3)) Answered by Ar Brandon last updated on 31/Jan/22 I=∫0π2x3cosec2xdx=−[x3cotx]0π2+3∫0π2x2cotxdx=3[x2ln(sinx)]0π2−6∫0π2xln(sin(x)dx Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: let-f-x-x-dt-1-t-2-t-4-1-prove-that-f-id-derivsble-and-calculate-f-x-2-devellpp-f-at-integr-serie-at-o-Next Next post: Question-165381 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.