0-pi-2-x-sec-x-csc-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 130958 by bramlexs22 last updated on 31/Jan/21 ∫0π/2xsecx+cscxdx Commented by benjo_mathlover last updated on 31/Jan/21 M=∫π/20xsecx+cscxdx=∫π/20π2−xsecx+cscxdx2M=π2∫π/20dxsecx+cscx;M=π4∫π/20sinx.cosxsinx+cosxdxM=π4∫π/20sinx.cosx2sin(x+π4)dx Commented by benjo_mathlover last updated on 31/Jan/21 M=π42∫3π/4π/412(sint−cost).12(cost+sint)sintdtM=π82∫3π/4π/42sin2t−1sintdt=π82(−2cost+ln∣csct+cott∣)π/43π/4M=π42[2+ln(2−1)] Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-65420Next Next post: Question-65427 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.