0-pi-2-x-sin-2-x-ln-sin-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 155252 by mnjuly1970 last updated on 27/Sep/21 ∫0π2x.sin2(x).ln(sin(x))dx Answered by phanphuoc last updated on 28/Sep/21 lnsinx=−ln2−∑k=1∞cos(2kx)k→I=∫0∞xsin2x(−ln2−Σcos(2kx)k)dx=−ln2∫0∞xsin2xdx−Σ12kx(1−cos2x)cos(2kx)youcanIBP→…… Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: find-1-arctan-ln-x-4-x-2-dx-Next Next post: Question-24184 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.